My 3.8 FHC is undergoing a full restoration.
I have had the Gearbox checked out and have come to the “easy” part of putting the shifter back on.
However, I can’t work out if I’m doing everything correctly - it seems so simple, but the maths doesn’t add up:
(Apologies for using metric).
Referring to the attached photo, I presume I need to insert parts B, C, D & E into A.
If so, then B is 19.1mm, C & D are 2.6mm each and E fully compressed in my vice is 3.8mm = Total 28.1mm
However A has an opening of only 26.0mm.
C & D are new parts C1908, and E (also new) is C1929.
Perhaps I have the wrong Part A? Or maybe the very top of the gearbox is non-original (the gearbox number matches my Heritage Certificate - except my box has CR on top and side whereas Certificate has JS - happy for feedback on this too)
The photos I have taken on the dismantling have missed this - I hope the answer will be quite simple as to what I am missing. Maybe I bought the wrong washers?
Thanks in advance,
Glenn












